3x^2+15x+40=4

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Solution for 3x^2+15x+40=4 equation: 



3x^2+15x+40=4

We move all terms to the left:

3x^2+15x+40-(4)=0

We add all the numbers together, and all the variables

3x^2+15x+36=0

a = 3; b = 15; c = +36;
Δ = b2-4ac
Δ = 152-4·3·36
Δ = -207
Delta is less than zero, so there is no solution for the equation

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